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9n^2-11n-10=0
a = 9; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·9·(-10)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{481}}{2*9}=\frac{11-\sqrt{481}}{18} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{481}}{2*9}=\frac{11+\sqrt{481}}{18} $
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